4x^2-32x-35=0

Solution for 4x^2-32x-35=0 equation:

4x^2-32x-35=0

a = 4; b = -32; c = -35;
Δ = b2-4ac
Δ = -322-4·4·(-35)
Δ = 1584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1584}=\sqrt{144*11}=\sqrt{144}*\sqrt{11}=12\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-12\sqrt{11}}{2*4}=\frac{32-12\sqrt{11}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+12\sqrt{11}}{2*4}=\frac{32+12\sqrt{11}}{8}
$